What is the current through an ideal pn - junction diode shown in figure below?

Question

What is the current through an ideal pn - junction diode shown in figure below? (A) Zero (B) 10 mA (C) 20 mA (D) 50 mA

Tardigrade Admin · Accepted Answer

The potential of p-side is more positive than that of n-side, hence, diode is in forward biasing. in forward biasing current flow is possible and I=(V/R) =((3-1)/100) =20 mA .

Q. What is the current through an ideal pn - junction diode shown in figure below?

Zero

10 mA

20 mA

50 mA

The potential of $p$ -side is more positive than that of $n$ -side, hence, diode is in forward biasing.
in forward biasing current flow is possible and $I = \frac{V}{R}$
$= \frac{( 3 - 1 )}{100}$
$= 20 m A$ .

Q. What is the current through an ideal pn - junction diode shown in figure below?

Zero

10 mA

20 mA

50 mA

The potential of p-side is more positive than that of n-side, hence, diode is in forward biasing. in forward biasing current flow is possible and I=RV​ =100(3−1)​ =20mA .

The potential of $p$ -side is more positive than that of $n$ -side, hence, diode is in forward biasing.
in forward biasing current flow is possible and $I = \frac{V}{R}$
$= \frac{( 3 - 1 )}{100}$
$= 20 m A$ .