Question

What is the correct value of Bohr magneton?

• A. $8.99\times 10^{-24}A{m}^2$
• B. $9.27\times 10^{-24}A{m}^2$
• C. $5.66\times 10^{-24}A{m}^2$
• D. $9.27\times 10^{-28}A{m}^2$

Answer 1

Answer: (B)

Bohr Magnetron
${\left({\mu }_l\right)}_{min}={\mu }_B=\frac{e}{4\pi m_e}h$
Here, $e=1.6\times 10^{-19}C$,
$h=6.64\times 10^{-34}Js$
$m_e=9.1\times 10^{-31}kg$
$\therefore {\mu }_B=\frac{1.60\times 10^{-19}\times 6.64\times 10^{-34}}{4\times 3.14\times 9.1\times 10^{-31}}$
$=9.27\times 10^{-24}A{m}^2$