What is the correct increasing order of extent of deprotonation of the following acids in its aqueous solution? (I) ( CH 3)2 CHCOOH (II) CH 3 CH 2 COOH (III) Cl 2 CHCH 2 COOH (IV) CH 3 CCl 2 COOH

Question

What is the correct increasing order of extent of deprotonation of the following acids in its aqueous solution? (I) ( CH 3)2 CHCOOH (II) CH 3 CH 2 COOH (III) Cl 2 CHCH 2 COOH (IV) CH 3 CCl 2 COOH (A) II < I < III < IV (B) IV < III < I < II (C) I < IV < III < II (D) I < II < II < IV

Tardigrade Admin · Accepted Answer

Electron withdrawing group (Cl) increases acidic strength while electron donating group (- CH 3) decreases acidic strength. Also magnitude of inductive effect decreases drastically on increasing distance, IV is stronger acid than III.

Two methyl groups (in I) gives greater +I effect than one methyl group (in II), hence I is a weaker acid than II.

Two -Cl from closer position in IV exert greater-I effect than the same from larger distance in III, hence IV is stronger acid than III.

Q. What is the correct increasing order of extent of deprotonation of the following acids in its aqueous solution?
(I) $(C H_{3})_{2} C H COO H$
(II) $C H_{3} C H_{2} COO H$
(III) $C l_{2} C H C H_{2} COO H$
(IV) $C H_{3} CC l_{2} COO H$

$II < I < III < I V$

$I V < III < I < II$

$I < I V < III < II$

$I < II < II < I V$

Q. What is the correct increasing order of extent of deprotonation of the following acids in its aqueous solution? (I) (CH3​)2​CHCOOH (II) CH3​CH2​COOH (III) Cl2​CHCH2​COOH (IV) CH3​CCl2​COOH

II<I<III<IV

IV<III<I<II

I<IV<III<II

I<II<II<IV

Q. What is the correct increasing order of extent of deprotonation of the following acids in its aqueous solution?
(I) $(C H_{3})_{2} C H COO H$
(II) $C H_{3} C H_{2} COO H$
(III) $C l_{2} C H C H_{2} COO H$
(IV) $C H_{3} CC l_{2} COO H$

$II < I < III < I V$

$I V < III < I < II$

$I < I V < III < II$

$I < II < II < I V$