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Tardigrade
Question
Physics
What is the conductivity of a semiconductor (in Ω-1 m -1 ) if electron density =5 × 1012 / cm 3 and hole density =8 × 1013 / cm 3 ? (μe=2.3 m 2 V -1 s -1, μh=0.01 m 2 V -1 s -1)
Q. What is the conductivity of a semiconductor (in
Ω
−
1
m
−
1
) if electron density
=
5
×
1
0
12
/
c
m
3
and hole density
=
8
×
1
0
13
/
c
m
3
?
(
μ
e
=
2.3
m
2
V
−
1
s
−
1
,
μ
h
=
0.01
m
2
V
−
1
s
−
1
)
1934
217
Semiconductor Electronics: Materials Devices and Simple Circuits
Report Error
A
5.634
4%
B
1.968
76%
C
3.421
11%
D
8.964
9%
Solution:
Here,
μ
e
=
2.3
m
2
V
−
1
s
−
1
μ
h
=
0.01
m
2
V
−
1
s
−
1
,
n
e
=
5
×
1
0
12
/
c
m
3
=
5
×
1
0
18
/
m
3
n
h
=
8
×
1
0
13
/
c
m
3
=
8
×
1
0
19
/
m
3
σ
=
e
(
n
e
μ
e
+
n
h
μ
h
)
=
1.6
×
1
0
−
19
[
(
5
×
1
0
18
)
×
2.3
+
(
8
×
1
0
19
)
×
0.01
]
=
1.6
×
1
0
−
1
[
11.5
+
0.8
]
=
1.968
Ω
−
1
m
−
1