What is the concentration of copper sulphate (in mol L-1) if 80 g of it is dissolved in enough water to make a final volume of 3 L?

Question

What is the concentration of copper sulphate (in mol L-1) if 80 g of it is dissolved in enough water to make a final volume of 3 L? (A) 0.0167 (B) 0.167 (C) 1.067 (D) 10.67

Tardigrade Admin · Accepted Answer

Molar mass of CuSO4 = 63.5 + 32 + 64 = 159.5 Moles of CuSO4 = (80/159.5) = 0.50 Volume of solution = 3 L Molarity = ( textMoles of solute/ textVolume of solution in L) = (0.50/3) =0.167 mol L-1

Q. What is the concentration of copper sulphate (in mol $L^{- 1}$ ) if $80 g$ of it is dissolved in enough water to make a final volume of $3 L$ ?

$0.0167$

$0.167$

$1.067$

$10.67$

Molar mass of $C u S O_{4} = 63.5 + 32 + 64 = 159.5$
Moles of $C u S O_{4} = \frac{80}{159.5} = 0.50$
Volume of solution $= 3 L$
Molarity $= \frac{Moles of solute}{Volume of solution in L} = \frac{0.50}{3}$
$= 0.167 m o l L^{- 1}$

Q. What is the concentration of copper sulphate (in mol L−1) if 80g of it is dissolved in enough water to make a final volume of 3L?

0.0167

0.167

1.067

10.67