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  4. What is the concentration of copper sulphate (in mol L-1) if 80 g of it is dissolved in enough water to make a final volume of 3 L?

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Q. What is the concentration of copper sulphate (in mol $L^{-1}$) if $80\, g$ of it is dissolved in enough water to make a final volume of $3\, L$?

Some Basic Concepts of Chemistry

Solution:

Molar mass of $CuSO_{4} = 63.5 + 32 + 64 = 159.5$
Moles of $CuSO_{4} = \frac{80}{159.5} = 0.50$
Volume of solution $= 3 L$
Molarity $= \frac{\text{Moles of solute}}{\text{Volume of solution in L}} = \frac{0.50}{3}$
$=0.167\, mol\, L^{-1}$