What is the colour corresponding to the wavelength of light emitted when the electron in a hydrogen atom undergoes transition from n = 4 to n = 2?

Question

What is the colour corresponding to the wavelength of light emitted when the electron in a hydrogen atom undergoes transition from n = 4 to n = 2? (A) Blue (B) Red (C) Yellow (D) Green

Tardigrade Admin · Accepted Answer

(1/λ)=R[(1/n21)-(1/n22)] =109677 [(1/22)-(1/42)]cm-1 =205644.4 cm-1 λ=(1/20564.4 cm-1) =486×10-7 cm or 486×10-9 m Colour corresponding to this wavelength is blue.

Q. What is the colour corresponding to the wavelength of light emitted when the electron in a hydrogen atom undergoes transition from $n = 4$ to $n = 2$ ?

Blue

Red

Yellow

Green

$\frac{1}{λ} = R [\frac{1}{n _{1}^{2}} - \frac{1}{n _{2}^{2}}]$
$= 109677$
$[\frac{1}{2 ^{2}} - \frac{1}{4 ^{2}}] c m^{- 1}$
$= 205644.4 c m^{- 1}$
$λ = \frac{1}{20564.4 c m ^{- 1}}$
$= 486 \times 1 0^{- 7} c m$ or $486 \times 1 0^{- 9} m$
Colour corresponding to this wavelength is blue.

Q. What is the colour corresponding to the wavelength of light emitted when the electron in a hydrogen atom undergoes transition from n=4 to n=2?

Blue

Red

Yellow

Green

λ1​=R[n12​1​−n22​1​] =109677 [221​−421​]cm−1 =205644.4cm−1 λ=20564.4cm−11​ =486×10−7cm or 486×10−9m Colour corresponding to this wavelength is blue.

Q. What is the colour corresponding to the wavelength of light emitted when the electron in a hydrogen atom undergoes transition from $n = 4$ to $n = 2$ ?

$\frac{1}{λ} = R [\frac{1}{n _{1}^{2}} - \frac{1}{n _{2}^{2}}]$
$= 109677$
$[\frac{1}{2 ^{2}} - \frac{1}{4 ^{2}}] c m^{- 1}$
$= 205644.4 c m^{- 1}$
$λ = \frac{1}{20564.4 c m ^{- 1}}$
$= 486 \times 1 0^{- 7} c m$ or $486 \times 1 0^{- 9} m$
Colour corresponding to this wavelength is blue.