Question

What is the area of the plates of a $3F$ parallel plate capacitor, if the separation between the plates is $5mm$ ?

• A. $9.281\times 10^9{m}^2$
• B. $4.529\times 10^9{m}^2$
• C. $1.694\times 10^9{m}^2$
• D. $12.981\times 10^9{m}^2$

Answer 1

Answer: (C)

Let the area be A
The separation between the plates $d=5mm=0.005m$
We know capacitance $C=\frac{{\epsilon }_{0}A}{d}$
$\Rightarrow A=\frac{Cd}{{\epsilon }_0}$
$=4\pi \times 3\times 0.005\times 9\times 10^9$
$=1.69\times 10^9{m}^2$