What is the angular momentum of H-atom orbital if its electron energy is -3.4 eV ?

Question

What is the angular momentum of H-atom orbital if its electron energy is -3.4 eV ? (A) 2.1 × 10-34 J s (B) 1.05 × 10-34 J s (C) 4.2 × 10-34 J s (D) 2.6 × 10-35 J s

Tardigrade Admin · Accepted Answer

We know, En=-(13.6/n2) eV For H-atom. -3.4=-(13.6/n2) ⇒ n2=(13.6/3.4)=4 ⇒ n=2 Now, angular momentum (m v r)=(n h/2 π) π =(2 × 6.6 × 10-34/2 × 3.14)=2.1 × 10-34 Js

Q. What is the angular momentum of H-atom orbital if its electron energy is $- 3.4 e V ?$

$2.1 \times 1 0^{- 34} J s$

$1.05 \times 1 0^{- 34} J s$

$4.2 \times 1 0^{- 34} J s$

$2.6 \times 1 0^{- 35} J s$

We know, $E_{n} = - \frac{13.6}{n ^{2}} e V$

For H-atom.

$- 3.4 = - \frac{13.6}{n ^{2}}$

$\Rightarrow n^{2} = \frac{13.6}{3.4} = 4 \Rightarrow n = 2$

Now, angular momentum $(m v r) = \frac{nh}{2 π} π$

$= \frac{2 \times 6.6 \times 1 0 ^{- 34}}{2 \times 3.14} = 2.1 \times 1 0^{- 34} J s$

Q. What is the angular momentum of H-atom orbital if its electron energy is −3.4eV?

2.1×10−34Js

1.05×10−34Js

4.2×10−34Js

2.6×10−35Js