What is the amount of chlorine evolved when 2 ampere of. current is passed for 30 minutes in an aqueous solution of NaCl ?

Question

What is the amount of chlorine evolved when 2 ampere of. current is passed for 30 minutes in an aqueous solution of NaCl ? (A) 66 g (B) 1.32 g (C) 33 g (D) 99 g

Tardigrade Admin · Accepted Answer

At Anode: Cl - longrightarrow 1 / 2 Cl 2+e- E Cl 2=(35.5 × 2/2)=35.5 w Cl 2=(E Cl 2 × I × t/96500)=(35.5 × 2 × 30 × 60/96500)=1.32 g

Q. What is the amount of chlorine evolved when $2$ ampere of. current is passed for $30$ minutes in an aqueous solution of $N a Cl ?$

$66 g$

$1.32 g$

$33 g$

$99 g$

At Anode : $C l^{-} ⟶ 1/2 C l_{2} + e^{-}$

$E_{C l_{2}} = \frac{35.5 \times 2}{2} = 35.5$

$w_{C l_{2}} = \frac{E _{C l_{2}} \times I \times t}{96500} = \frac{35.5 \times 2 \times 30 \times 60}{96500} = 1.32 g$

Q. What is the amount of chlorine evolved when 2 ampere of. current is passed for 30 minutes in an aqueous solution of NaCl?

66g

1.32g

33g

99g