What is the amount of charge possessed by 1 kg of electrons? Given that mass of an electrons is 9.1 × 10-31 kg.

Question

What is the amount of charge possessed by 1 kg of electrons? Given that mass of an electrons is 9.1 × 10-31 kg. (A) 6.25 × 1010 C (B) 1.76 × 1011 C (C) 1.76 × 1010 C (D) 1.25 × 1010 C

Tardigrade Admin · Accepted Answer

n=(M/me)=(1 kg /9.1 × 10-31 kg )=1.1 × 1030 Therefore, charge on 1 kg of electrons, q=n e=1.1 × 1030 × 1.6 × 10-19 =1.76 × 1011 C

Q. What is the amount of charge possessed by $1 k g$ of electrons? Given that mass of an electrons is $9.1 \times 1 0^{- 31} k g$ .

$6.25 \times 1 0^{10} C$

$1.76 \times 1 0^{11} C$

$1.76 \times 1 0^{10} C$

$1.25 \times 1 0^{10} C$

$n = \frac{M}{m _{e}} = \frac{1 k g}{9.1 \times 1 0 ^{- 31} k g} = 1.1 \times 1 0^{30}$
Therefore, charge on $1 k g$ of electrons,
$q = n e = 1.1 \times 1 0^{30} \times 1.6 \times 1 0^{- 19}$
$= 1.76 \times 1 0^{11} C$

Q. What is the amount of charge possessed by 1kg of electrons? Given that mass of an electrons is 9.1×10−31kg.

6.25×1010C

1.76×1011C

1.76×1010C

1.25×1010C