What is the actual volume occupied by water molecules present in 20 cm3 of water ?

Question

What is the actual volume occupied by water molecules present in 20 cm3 of water ? (A)  20 cm3 (B)  10 cm3 (C)  40 cm3 (D) 24.89 cm3

Tardigrade Admin · Accepted Answer

Density of water =1 g / cc Therefore 20 cm 3 weights 20 g of water molecules. So number of moles of water =(20/18)=1.11 moles 1 mole occupies 22.4 L. Therefore 1.11 moles occupies 24.89 L, i.e., 24.89 dm 3.

Q. What is the actual volume occupied by water molecules present in $20 c m^{3}$ of water ?

$20 c m^{3}$

$10 c m^{3}$

$40 c m^{3}$

$24.89 c m^{3}$

Density of water $= 1 g / cc$

Therefore $20 c m^{3}$ weights 20 g of water molecules.

So number of moles of water $= \frac{20}{18} = 1.11$ moles

1 mole occupies $22.4 L$ .

Therefore $1.11$ moles occupies $24.89 L$ , i.e., $24.89 d m^{3}$ .

Q. What is the actual volume occupied by water molecules present in 20cm3 of water ?

20cm3

10cm3

40cm3

24.89cm3