Question

What is ratio of Bohr magneton to the nuclear magneton?

• A. $m_p/m_e$
• B. $m_p^2/m_e^2$
• C. $1$
• D. $\frac{m_e}{m_p}$

Answer 1

Answer: (A)

Magnetic moment associated with electrons orbitting around the nucleus is given in terms of Bohr magneton $\left({\mu }_B\right)$
${\mu }_B=\frac{eh}{2m_e}$
e = electronic charge, me = electronic mass.
In nuclear physics, magnetic moments associated with the spins of protons and neutrons are expressed in nuclear magnetons $\left({\mu }_N\right)$
${\mu }_N=\frac{eh}{2m_p}$
$m_p$ = mass of a proton.
$\Rightarrow \frac{{\mu }_B}{{\mu }_N}=\frac{m_p}{m_e}$