Question

What is particle x in the following nuclear reaction
$\_4^{}B{e}^9+\_2^{}H{e}^4\to \_6^{}{C}_{}^{12}+x$

• A. Electron
• B. Proton
• C. Neutron
• D. Photon

Answer 1

Answer: (C)

$\_4^{}B{e}^9+\_2^{}H{e}^4\to \_6^{}{C}_{}^{12}+\_0^{}{n}_{}^1$ (Neutron)