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  4. What is particle x in the following nuclear reaction 4Be9+ 2He4 arrow 6C12+x

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Q. What is particle x in the following nuclear reaction
$\_{4}^{}Be^{9}+\_{2}^{}He^{4} \rightarrow \_{6}^{}C_{}^{12}+x$

NTA AbhyasNTA Abhyas 2020

Solution:

$\_{4}^{}Be^{9}+\_{2}^{}He^{4} \rightarrow \_{6}^{}C_{}^{12}+\_{0}^{}n_{}^{1}$ (Neutron)