Question

What is order with respect to $A,B,C$, respectively

[A]	[B]	[C]	rate(M/sec.)
0.2	0.1	0.02	$8.08\times 10^{-3}$
0.1	0.2	0.02	$2.01\times 10^{-3}$
0.1	1.8	0.18	$6.03\times 10^{-3}$
0.2	0.1	0.08	$6.464\times 10^{-2}$

• A. -1,1, 3/2
• B. -1, 1, 1/2
• C. 1, 3/2, -1
• D. 1, -1, 3/2

Answer 1

Answer: (D)

If rate $=k{\left[A\right]}^x{\left[B\right]}^y{\left[C\right]}^z$
From first two given data
$8.08\times 10^{-3}=k{\left[0.2\right]}^x\times {\left[0.1\right]}^y{\left[0.02\right]}^z....\left(1\right)$
$2.01\times 10^{-3}=k{\left[0.1\right]}^x\times {\left[0.2\right]}^y{\left[0.02\right]}^z....\left(2\right)$
Divide $\left(1\right)$ by $\left(2\right)$ we get, $4=2^x{\left(1/2\right)}^y$
Similarly, from second and third data
${\left(9\right)}^y{\left(9\right)}^z=32y+2z=1$.
From first and fourth data $4^z=8=2^{3}2z=3$.
So $z=3/2,y=-1,x=1$