Question

What is order with respect to $A, B, C$, respectively

[A]	[B]	[C]	rate(M/sec.)
0.2	0.1	0.02	$8.08 \times 10^{-3}$
0.1	0.2	0.02	$2.01 \times 10^{-3}$
0.1	1.8	0.18	$6.03 \times 10^{-3}$
0.2	0.1	0.08	$6.464 \times 10^{-2}$

• A. -1,1, 3/2
• B. -1, 1, 1/2
• C. 1, 3/2, -1
• D. 1, -1, 3/2

Answer 1

Answer: (D)

If rate $= k\left[A\right]^{x} \left[B\right]^{y} \left[C\right]^{z}$
From first two given data
$8.08 \times 10^{-3} = k \left[0.2\right]^{x}\times \left[0.1\right]^{y}\left[0.02\right]^{z}.... \left(1\right)$
$2.01 \times 10^{-3} = k \left[0.1\right]^{x}\times \left[0.2\right]^{y}\left[0.02\right]^{z}.... \left(2\right)$
Divide $\left(1\right)$ by $\left(2\right)$ we get, $4 = 2^{x} \left(1/2\right)^{y}$
Similarly, from second and third data
$\left(9\right)^{y}\left(9\right)^{z} = 3 2y+2z= 1$.
From first and fourth data $4^{z} = 8 = 2^{3}2z = 3$.
So $z = 3/2, y=- 1, \,x = 1$