What is Δ E for system that does 500 cal-of work on surrounding and 300 cal of heat is absorbed by the system ?

Question

What is Δ E for system that does 500 cal-of work on surrounding and 300 cal of heat is absorbed by the system ? (A) -200 cal (B) -300 cal (C) + 200 cal (D) +300 cal

Tardigrade Admin · Accepted Answer

From first law of thermodynamic. Δ E=q+ W Given q=+300 cal (∵ heat is absorbed) W-500 cal (∵ work is done on surroundings). ∴ Δ E=q+ W =300+(-500) =-200 cal.

Q. What is $Δ E$ for system that does $500 c a l$ -of work on surrounding and $300 c a l$ of heat is absorbed by the system ?

-200 cal

-300 cal

+ 200 cal

+300 cal

From first law of thermodynamic.
$Δ E = q + W$
Given $q = + 300 c a l$ ( $∵$ heat is absorbed)
$W - 500 c a l$
$(∵$ work is done on surroundings).
$∴ Δ E = q + W$
$= 300 + (- 500)$
$= - 200 c a l .$

Q. What is ΔE for system that does 500cal-of work on surrounding and 300cal of heat is absorbed by the system ?