What is bond dissociation energy of HCl , DHf ( HCl )=-93, B . E .( H 2)=434, B . E .( Cl 2)=242( in kJ / mol ) ?

Question

What is bond dissociation energy of HCl , DHf ( HCl )=-93, B . E .( H 2)=434, B . E .( Cl 2)=242( in kJ / mol ) ? (A) 532 kJ/mol (B) 431 kJ/mol (C) 332 kJ/mol (D) 232 kJ/mol

Tardigrade Admin · Accepted Answer

(1/2) H 2 (1/2) Cl 2 HCl H f B.E. ( H ) (1/2) B.E. ( Cl 2) (1/2) B.E. ( HCl ) =(1/2)(434)+(1/2)(242) =431 kJ mol -1

Q. What is bond dissociation energy of $H Cl, DH f (H Cl) = - 93, B . E . (H_{2}) = 434, B . E . (C l_{2}) = 242 ($ in $k J / m o l)?$

532 kJ/mol

431 kJ/mol

332 kJ/mol

232 kJ/mol

$\frac{1}{2} H_{2} \frac{1}{2} C l_{2} H Cl$
$H_{f}$ B.E. $(H) \frac{1}{2}$ B.E. $(C l_{2}) \frac{1}{2}$ B.E. $(H Cl)$
$= \frac{1}{2} (434) + \frac{1}{2} (242)$
$= 431 k J m o l^{- 1}$

Q. What is bond dissociation energy of HCl,DHf(HCl)=−93,B.E.(H2​)=434,B.E.(Cl2​)=242( in kJ/mol)?