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Q. What is bond dissociation energy of $HCl , DHf ( HCl )=-93, B . E .\left( H _{2}\right)=434, B . E .\left( Cl _{2}\right)=242($ in $kJ / mol ) ?$

JIPMERJIPMER 2018Thermodynamics

Solution:

$\frac{1}{2} H _{2} \quad \frac{1}{2} Cl _{2} \quad HCl$
$H _{ f } \quad$ B.E. $( H ) \quad \frac{1}{2} \quad$ B.E. $\left( Cl _{2}\right) \quad \frac{1}{2} \quad$ B.E. $( HCl )$
$=\frac{1}{2}(434)+\frac{1}{2}(242)$
$=431 \,kJ\,mol ^{-1}$