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Chemistry
What is bond dissociation energy of HCl , DHf ( HCl )=-93, B . E .( H 2)=434, B . E .( Cl 2)=242( in kJ / mol ) ?
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Q. What is bond dissociation energy of $HCl , DHf ( HCl )=-93, B . E .\left( H _{2}\right)=434, B . E .\left( Cl _{2}\right)=242($ in $kJ / mol ) ?$
JIPMER
JIPMER 2018
Thermodynamics
A
532 kJ/mol
B
431 kJ/mol
C
332 kJ/mol
D
232 kJ/mol
Solution:
$\frac{1}{2} H _{2} \quad \frac{1}{2} Cl _{2} \quad HCl$
$H _{ f } \quad$ B.E. $( H ) \quad \frac{1}{2} \quad$ B.E. $\left( Cl _{2}\right) \quad \frac{1}{2} \quad$ B.E. $( HCl )$
$=\frac{1}{2}(434)+\frac{1}{2}(242)$
$=431 \,kJ\,mol ^{-1}$