What fraction of Fe exists as Fe (III) in Fe 0.96 O ? (Consider Fe 0.96 to be made up of Fe (II) and Fe (III) only)

Question

What fraction of Fe exists as Fe (III) in Fe 0.96 O ? (Consider Fe 0.96 to be made up of Fe (II) and Fe (III) only) (A) (1/12) (B) 0.08 (C) (1/16) (D) (1/20)

Tardigrade Admin · Accepted Answer

Fe 0.96 O Let, No. of ions of Fe +2=x No. of ions of Fe +3=0.96- x Now, ( x )(+2)+(0.96- x )(+3)+1(-2)=0 2 x+2.88-3 x-2=0 x =0.88 ∴ Fraction of Fe +3 ions =(0.08/0.96)=(1/12).

Q. What fraction of $F e$ exists as $F e$ (III) in $F e_{0.96} O$ ? (Consider $F e_{0.96}$ to be made up of $F e$ (II) and $F e$ (III) only)

$\frac{1}{12}$

$0.08$

$\frac{1}{16}$

$\frac{1}{20}$

$F e_{0.96} O$
Let, No. of ions of $F e^{+ 2} = x$
No. of ions of $F e^{+ 3} = 0.96 - x$
Now, $(x) (+ 2) + (0.96 - x) (+ 3) + 1 (- 2) = 0$
$2 x + 2.88 - 3 x - 2 = 0$
$x = 0.88$
$∴$ Fraction of $F e^{+ 3}$ ions $= \frac{0.08}{0.96} = \frac{1}{12}$ .

Q. What fraction of Fe exists as Fe (III) in Fe0.96​O ? (Consider Fe0.96​ to be made up of Fe (II) and Fe (III) only)

121​

0.08

161​

201​