What bond order does O22- have

Question

What bond order does O22- have (A) 3 (B) 2 (C) 1 (D) 1/2

Tardigrade Admin · Accepted Answer

Molecular orbital configuration of O 22-=σ 1 s2, σx 1 s2, σ 2 s2, σx 2 s2, σ 2 p2(x) Bond order =(1/2)(10-8) π 2 py2, π 2 p(z)2, πx 2 p(y)2, πx 2 p(z)2

Q. What bond order does $O_{2}^{2 -}$ have

3

2

1

1/2

Molecular orbital configuration of
$O_{2}^{2 -} = σ 1 s^{2}, σ^{x} 1 s^{2}, σ 2 s^{2}, σ^{x} 2 s^{2}, σ 2 p^{2} (x)$
Bond order $= \frac{1}{2} (10 - 8)$
$π 2 p_{y}^{2}, π 2 p_{(z)}^{2}, π^{x} 2 p_{(y)}^{2}, π^{x} 2 p_{(z)}^{2}$

Q. What bond order does O22−​ have

3

2

1

1/2

Molecular orbital configuration of O22−​=σ1s2,σx1s2,σ2s2,σx2s2,σ2p2(x) Bond order =21​(10−8) π2py2​,π2p(z)2​,πx2p(y)2​,πx2p(z)2​

Q. What bond order does $O_{2}^{2 -}$ have

Molecular orbital configuration of
$O_{2}^{2 -} = σ 1 s^{2}, σ^{x} 1 s^{2}, σ 2 s^{2}, σ^{x} 2 s^{2}, σ 2 p^{2} (x)$
Bond order $= \frac{1}{2} (10 - 8)$
$π 2 p_{y}^{2}, π 2 p_{(z)}^{2}, π^{x} 2 p_{(y)}^{2}, π^{x} 2 p_{(z)}^{2}$