Question

What amount of dioxygen (in gram) contains $1.8\times 10^{22}$ molecules ?

• A. 0.0960
• B. 0.960
• C. 9.60
• D. 96.0

Answer 1

Answer: (B)

$32g$ dioxygen contains $6.022\times 10^{23}$ molecules of dioxygen of $6.022\times 10^{23}$ molecules of dioxygen contain dioxygen in gram $=32$

$\therefore 18\times 10^{22}$ molecules contain dioxygen in gram

$=\frac{32\times 1.8\times 10^{22}}{6.022\times 10^{23}}=0.955=0.960$