What amount of Cl2 gas liberated at anode, if 1 ampere current is passed for 30 minute from NaCl solution?

Question

What amount of Cl2 gas liberated at anode, if 1 ampere current is passed for 30 minute from NaCl solution? (A) 0.66 mol (B) 0.33 mol (C) 0.66 g (D) 0.33 g

Tardigrade Admin · Accepted Answer

2 Cl - arrow underset1 moleCl 2+ underset2 × 96500 textcoulomb2 e-( At anode) Q =i t=1 × 30 × 60 =1800 coulomb The amount of chlorine liberated by passing 1800 coulomb of electric charge =(1 × 1800 × 71/2 × 96500)=0.66 g

Q. What amount of $C l_{2}$ gas liberated at anode, if $1$ ampere current is passed for $30$ minute from $N a Cl$ solution?

0.66 mol

0.33 mol

0.66 g

0.33 g

$2 C l^{-} \to 1 m o l e C l_{2} + 2 \times 96500 coulomb 2 e^{-} (A t an o d e)$
$Q = i t = 1 \times 30 \times 60$
$= 1800$ coulomb
The amount of chlorine liberated by passing 1800 coulomb of electric charge
$= \frac{1 \times 1800 \times 71}{2 \times 96500} = 0.66 g$

Q. What amount of Cl2​ gas liberated at anode, if 1 ampere current is passed for 30 minute from NaCl solution?