Weight of a body of mass m decreases by 1 % when it is raised to height h above the earth’s surface. If the body is taken to a depth h in a mine, change in its weight is

Question

Weight of a body of mass m decreases by 1 % when it is raised to height h above the earth’s surface. If the body is taken to a depth h in a mine, change in its weight is (A) 2% decrease (B) 0.5% decrease (C) 1% increase (D) 0.5% increase

Tardigrade Admin · Accepted Answer

For height (Δ g/g) × 100 %=(2 h/R)=1 %; For depth (Δ g/g) × 100 % =(d/R)=(h/R)=(1/2) %=0.5 %

Q. Weight of a body of mass $m$ decreases by $1%$ when it is raised to height h above the earth’s surface. If the body is taken to a depth h in a mine, change in its weight is

2% decrease

0.5% decrease

1% increase

0.5% increase

For height $\frac{Δ g}{g} \times 100% = \frac{2 h}{R} = 1%$ ;
For depth $\frac{Δ g}{g} \times 100%$
$= \frac{d}{R} = \frac{h}{R} = \frac{1}{2} % = 0.5%$

Q. Weight of a body of mass m decreases by 1% when it is raised to height h above the earth’s surface. If the body is taken to a depth h in a mine, change in its weight is