We have three aqueous solutions of NaCl labelled as (A),(B) and (C) with concentration of 0.1 M, 0.01 M and 0.001 M, respectively. The value of van't Hoff factor of these solutions will be in order

Question

We have three aqueous solutions of NaCl labelled as (A),(B) and (C) with concentration of 0.1 M, 0.01 M and 0.001 M, respectively. The value of van't Hoff factor of these solutions will be in order (A) iA < iB < iC (B) iA>iB>iC (C) iA=iB=iC (D) iA < iB > iC

Tardigrade Admin · Accepted Answer

NaCl is a strong electrolyte. For strong electrolytes, the value of 'i' remain same on dilutions, as they completely dissociate on dilutions.

Q. We have three aqueous solutions of $N a Cl$ labelled as $(A), (B)$ and $(C)$ with concentration of $0.1 M, 0.01 M$ and $0.001 M$ , respectively. The value of van't Hoff factor of these solutions will be in order

$i_{A} < i_{B} < i_{C}$

$i_{A} > i_{B} > i_{C}$

$i_{A} = i_{B} = i_{C}$

$i_{A} < i_{B} > i_{C}$

$N a Cl$ is a strong electrolyte. For strong electrolytes, the value of ' $i$ ' remain same on dilutions, as they completely dissociate on dilutions.

Q. We have three aqueous solutions of NaCl labelled as (A),(B) and (C) with concentration of 0.1M,0.01M and 0.001M, respectively. The value of van't Hoff factor of these solutions will be in order

iA​<iB​<iC​

iA​>iB​>iC​

iA​=iB​=iC​

iA​<iB​>iC​