Wavelength of H+ion with kinetic energy 1.68 eV is

Question

Wavelength of H+ion with kinetic energy 1.68 eV is (A) 1.22 nm (B) 0.22 nm (C) 0.022 nm (D) 0.122 nm

Tardigrade Admin · Accepted Answer

Given, kinetic energy of H+ion =1.68 eV Mass of proton =1.6726 × 10-27 kg We calculate, the wavelength of H+ion as follows: λ=(h/√2 Em) Here, E= kinetic energy, m= mass of proton h=6.62 × 10-34 k gm 2 s -1 =(6.62 × 10-34/√2 × 1.67 × 10-27 × E) =(0.286/√E(e V)) mathringA=(0.286/√1.68) mathringA=0.220 mathringA=0.022 nm

Q. Wavelength of $H^{+}$ ion with kinetic energy $1.68 e V$ is

$1.22 nm$

$0.22 nm$

$0.022 nm$

$0.122 nm$

Q. Wavelength of H+ion with kinetic energy 1.68eV is

1.22nm

0.22nm

0.022nm

0.122nm

Q. Wavelength of $H^{+}$ ion with kinetic energy $1.68 e V$ is

$1.22 nm$

$0.22 nm$

$0.022 nm$

$0.122 nm$