Water rises in a capillary upto a extension height such that upward force of surface tension balances the force of 75 × 10-4 N due to weight of water. If surface tension of water is 6 × 10-2 N / m. The internal circumference of the capillary must be

Question

Water rises in a capillary upto a extension height such that upward force of surface tension balances the force of 75 × 10-4 N due to weight of water. If surface tension of water is 6 × 10-2 N / m. The internal circumference of the capillary must be (A) 12.5 × 10-2 m (B) 6.5 × 10-2 m (C) 0.50 × 10-2 m (D) 1.25 × 10-2 m

Tardigrade Admin · Accepted Answer

F =T L L =(F/L)=(75 × 10-4/6 × 10-2) =12.5 × 10-2 m

Q. Water rises in a capillary upto a extension height such that upward force of surface tension balances the force of $75 \times 1 0^{- 4} N$ due to weight of water. If surface tension of water is $6 \times 1 0^{- 2} N / m$ . The internal circumference of the capillary must be

$12.5 \times 1 0^{- 2} m$

$6.5 \times 1 0^{- 2} m$

$0.50 \times 1 0^{- 2} m$

$1.25 \times 1 0^{- 2} m$

$F = T L$
$L = \frac{F}{L} = \frac{75 \times 1 0 ^{- 4}}{6 \times 1 0 ^{- 2}}$
$= 12.5 \times 1 0^{- 2} m$

Q. Water rises in a capillary upto a extension height such that upward force of surface tension balances the force of 75×10−4N due to weight of water. If surface tension of water is 6×10−2N/m. The internal circumference of the capillary must be

12.5×10−2m

6.5×10−2m

0.50×10−2m

1.25×10−2m