Water is flowing in a river at 2 ms-1 . The river is 50 m wide and has an average depth of 5 m . The power available from the current in the river is (Density of water = 1000 kg m-3 )

Question

Water is flowing in a river at 2 ms-1 . The river is 50 m wide and has an average depth of 5 m . The power available from the current in the river is (Density of water = 1000 kg m-3 ) (A)  0.5 MW  (B)  1 MW  (C)  1.5 MW  (D)  2 MW

Tardigrade Admin · Accepted Answer

Power = Kinetic energy of water flowing per second = (1/2) × area of cross-section × density × (velocity) 3 = (1/2) × 50× 5× 1000× 23 W = 106 W= 1 MW

Q. Water is flowing in a river at $2 m s^{- 1}$ . The river is $50 m$ wide and has an average depth of $5 m$ . The power available from the current in the river is
(Density of water $= 1000 k g m^{- 3}$ )

$0.5 M W$

$1 M W$

$1.5 M W$

$2 M W$

Power $=$ Kinetic energy of water flowing per second
$= \frac{1}{2} \times$ area of cross-section $\times$ density $\times$ (velocity) $^{3}$
$= \frac{1}{2} \times 50 \times 5 \times 1000 \times 2^{3} W$
$= 1 0^{6} W = 1 M W$

Q. Water is flowing in a river at 2ms−1 . The river is 50m wide and has an average depth of 5m . The power available from the current in the river is (Density of water =1000kgm−3 )

0.5MW

1MW

1.5MW

2MW