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Q. Water is flowing in a river at $ 2 \,ms^{-1} $ . The river is $ 50\, m $ wide and has an average depth of $ 5\, m $ . The power available from the current in the river is
(Density of water $ = 1000\, kg\, m^{-3} $ )

Work, Energy and Power

Solution:

Power $ = $ Kinetic energy of water flowing per second
$ = \frac{1}{2} \times $ area of cross-section $ \times $ density $ \times $ (velocity) $ ^{3} $
$ = \frac{1}{2} \times 50\times 5\times 1000\times 2^{3}\,W $
$ = 10^{6}\,W= 1\,MW $