Water is flowing in a horizontal pipe of nonuniform area of cross- section. The velocity of water at a place, where the radius of pipe is 0.01 m is 25 m / s. What will be the velocity of water where the radius of pipe is 0.02 m ?

Question

Water is flowing in a horizontal pipe of nonuniform area of cross- section. The velocity of water at a place, where the radius of pipe is 0.01 m is 25 m / s. What will be the velocity of water where the radius of pipe is 0.02 m ? (A) 7.25 m/s (B) 6.75 m/s (C) 6.25 m/s (D) None of these

Tardigrade Admin · Accepted Answer

From principle of continuity ( V 1/ V 2)=( r 22/ r 12) ⇒ =(25/ V 2)=((0.02)2/(0.01)2)

Q. Water is flowing in a horizontal pipe of nonuniform area of cross- section. The velocity of water at a place, where the radius of pipe is $0.01 m$ is $25 m / s$ . What will be the velocity of water where the radius of pipe is $0.02 m$ ?

7.25 m/s

6.75 m/s

6.25 m/s

None of these

From principle of continuity
$\frac{V _{1}}{V _{2}} = \frac{r _{2}^{2}}{r _{1}^{2}}$
$\Rightarrow= \frac{25}{V _{2}} = \frac{( 0.02 ) ^{2}}{( 0.01 ) ^{2}}$

Q. Water is flowing in a horizontal pipe of nonuniform area of cross- section. The velocity of water at a place, where the radius of pipe is 0.01m is 25m/s. What will be the velocity of water where the radius of pipe is 0.02m ?