1. Tardigrade
  2. Question
  3. Physics
  4. Water is flowing in a horizontal pipe of nonuniform area of cross- section. The velocity of water at a place, where the radius of pipe is 0.01 m is 25 m / s. What will be the velocity of water where the radius of pipe is 0.02 m ?

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Q. Water is flowing in a horizontal pipe of nonuniform area of cross- section. The velocity of water at a place, where the radius of pipe is $0.01 \,m$ is $25 \,m / s$. What will be the velocity of water where the radius of pipe is $0.02\, m$ ?

Solution:

From principle of continuity
$\frac{ V _{1}}{ V _{2}}=\frac{ r _{2}^{2}}{ r _{1}^{2}} $
$\Rightarrow =\frac{25}{ V _{2}}=\frac{(0.02)^{2}}{(0.01)^{2}}$