Q.
Water is filled in a cylindrical container to a height of 3m. The ratio of the cross-sectional area of the orifice and the beaker is 0.1. The square of the speed of the liquid coming out from the orifice is (g=10m/s2)
let A= cross-sectional of tank a= cross-section hole V= velocity with which level decreases v= velocity of efflux
From equation of continuity, av=AV ⇒V=Aav
By using Bernoullis theorem for energy per unit volume.
Energy per unit volume at point A= energy per unit volume at point B p+ρgh+21ρv2=p+0+21ρv2 ⇒v2=1−(Aa)22gh=1−(0.1)22×10×(3−0.525) =50(m/s)2