Water is falling on the blades of a turbine at a rate of 3000 kg minute- 1. The height of the falls is 200 m. The power given to the turbine is (Assume g=10 m s- 2 )

Question

Water is falling on the blades of a turbine at a rate of 3000 kg minute- 1. The height of the falls is 200 m. The power given to the turbine is (Assume g=10 m s- 2 ) (A) 200 kW (B) 100 kW (C) 10 kW (D) 1 kW

Tardigrade Admin · Accepted Answer

Power =( text work done / text time ) But work done is equal to the potential energy of the falling water. Power =(m g h/t) But (m/t)=3000 kg minute - 1=(3000/60) kgs- 1 Power =(3000/60) × 10× 200=100 kW

Q. Water is falling on the blades of a turbine at a rate of $3000 k g$ $min u t e^{- 1} .$ The height of the falls is $200 m .$ The power given to the turbine is (Assume $g = 10 m s^{- 2}$ )

$200 kW$

$100 kW$

$10 kW$

$1 kW$

Power $= \frac{work done}{time}$
But work done is equal to the potential energy of the falling water.
Power $= \frac{m g h}{t}$
But $\frac{m}{t} = 3000 k g$ minute $_^{- 1} = \frac{3000}{60} k g s^{- 1}$
Power $= \frac{3000}{60} \times 10 \times 200 = 100 kW$

Q. Water is falling on the blades of a turbine at a rate of 3000kg minute−1. The height of the falls is 200m. The power given to the turbine is (Assume g=10ms−2 )

200kW

100kW

10kW

1kW