Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. Water is falling on the blades of a turbine at a rate of $3000\,kg$ $minute^{- 1}.$ The height of the falls is $200\,m.$ The power given to the turbine is (Assume $g=10\,m\,s^{- 2}$ )

NTA AbhyasNTA Abhyas 2022

Solution:

Power $=\frac{\text{ work done }}{\text{ time }}$
But work done is equal to the potential energy of the falling water.
Power $=\frac{m g h}{t}$
But $\frac{m}{t}=3000\,kg$ minute $\_{}^{- 1}=\frac{3000}{60}\,kgs^{- 1}$
Power $=\frac{3000}{60}\,\times 10\times 200=100\,kW$