Water drops fall at regular intervals from a tab which is hm above the ground. After how many seconds does the first drop reach the ground?

Question

Water drops fall at regular intervals from a tab which is hm above the ground. After how many seconds does the first drop reach the ground? (A) √(2 h/g) (B) √( h /2 g ) (C) ( h /2 g ) (D) (2 h/g)

Tardigrade Admin · Accepted Answer

h = ut +(1/2) gt 2 ⇒ h =(1/2) gt 2[∵ u =0] ∴ t =√2 h / g

Q. Water drops fall at regular intervals from a tab which is hm above the ground. After how many seconds does the first drop reach the ground?

$\frac{2 h}{g}$

$\frac{h}{2 g}$

$\frac{h}{2 g}$

$\frac{2 h}{g}$

$h = u t + \frac{1}{2} g t^{2}$
$\Rightarrow h = \frac{1}{2} g t^{2} [∵ u = 0]$
$∴ t = 2 h / g$

Q. Water drops fall at regular intervals from a tab which is hm above the ground. After how many seconds does the first drop reach the ground?

g2h​​

2gh​​

2gh​

g2h​

h=ut+21​gt2 ⇒h=21​gt2[∵u=0] ∴t=2h/g​

$\frac{2 h}{g}$

$\frac{h}{2 g}$

$\frac{h}{2 g}$

$\frac{2 h}{g}$

$h = u t + \frac{1}{2} g t^{2}$
$\Rightarrow h = \frac{1}{2} g t^{2} [∵ u = 0]$
$∴ t = 2 h / g$