Volume versus temperature graphs for a given mass of an ideal gas are shown in figure at two different values of constant pressure. What can be inferred about relation between P1 and P2 ?

Question

Volume versus temperature graphs for a given mass of an ideal gas are shown in figure at two different values of constant pressure. What can be inferred about relation between P1 and P2 ? (A) P1 > P2 (B) P1 = P2 (C) P1 < P2 (D) data is insufficient

Tardigrade Admin · Accepted Answer

According to Charles law V propto T or (V/T) = constant = (1/P) As in graph, slope at P2 is more than slope at P1, ∴ P 1 > P2

Q. Volume versus temperature graphs for a given mass of an ideal gas are shown in figure at two different values of constant pressure. What can be inferred about relation between $P_{1}$ and $P_{2}$ ?

$P_{1} > P_{2}$

$P_{1} = P_{2}$

$P_{1} < P_{2}$

data is insufficient

According to Charles law
$V \propto T$ or $\frac{V}{T} =$ constant $= \frac{1}{P}$
As in graph, slope at $P_{2}$ is more than slope at $P_{1}$ ,
$∴ P_{1} > P_{2}$

Q. Volume versus temperature graphs for a given mass of an ideal gas are shown in figure at two different values of constant pressure. What can be inferred about relation between P1​ and P2​ ?

P1​>P2​

P1​=P2​

P1​<P2​