Volume of a gas at NTP is 1.12× 10-7cm3 . The number of molecules in it is

Question

Volume of a gas at NTP is 1.12× 10-7cm3 . The number of molecules in it is (A)  3.01× 1012  (B)  3.01× 1024  (C)  3.01× 1023  (D)  3.01× 1020

Tardigrade Admin · Accepted Answer

Given, V=1.12 × 10-7 cm 3 ∵ 22400 cm 3 of the gas at STP has molecules =6.02 × 1023 ∴ 1.12 × 10-7 cm 3 of the gas at STP will have molecules =(6.02 × 1023/22400) × 1.12 × 10-7 =3.01 × 1012 molecules

Q. Volume of a gas at NTP is $1.12 \times 10^{- 7} c m^{3}$ . The number of molecules in it is

$3.01 \times 10^{12}$

$3.01 \times 10^{24}$

$3.01 \times 10^{23}$

$3.01 \times 10^{20}$

Given, $V = 1.12 \times 1 0^{- 7} c m^{3}$
$∵ 22400 c m^{3}$ of the gas at STP has molecules
$= 6.02 \times 1 0^{23}$
$∴ 1.12 \times 1 0^{- 7} c m^{3}$ of the gas at STP will have molecules
$= \frac{6.02 \times 1 0 ^{23}}{22400} \times 1.12 \times 1 0^{- 7}$
$= 3.01 \times 1 0^{12}$ molecules

Q. Volume of a gas at NTP is 1.12×10−7cm3 . The number of molecules in it is

3.01×1012

3.01×1024

3.01×1023

3.01×1020