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Tardigrade
Question
Chemistry
Volume of 0.1 M NaOH needed for the neutralisation of 20 mL of 0.05 M oxalic acid is
Q. Volume of
0.1
M
N
a
O
H
needed for the neutralisation of
20
m
L
of
0.05
M
oxalic acid is
5530
226
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UP CPMT 2010
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A
10
m
L
33%
B
15
m
L
30%
C
20
m
L
25%
D
30
m
L
11%
Solution:
Meq. of
N
a
O
H
= Meq. of oxalic acid ;
0.1
×
V
=
20
×
0.05
×
2
⇒
V
=
20
m
L