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  4. Volume of 0.1 M NaOH needed for the neutralisation of 20 mL of 0.05 M oxalic acid is

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Q. Volume of $0.1 \,M\, NaOH$ needed for the neutralisation of $20\, mL$ of $0.05\, M$ oxalic acid is

UP CPMTUP CPMT 2010Some Basic Concepts of Chemistry

Solution:

Meq. of $NaOH$ = Meq. of oxalic acid ;
$0.1 \times V = 20 \times 0.05 \times 2$
$\Rightarrow V=20\, mL$