Question

Volume occupied by one molecule of water $(density=1gc{m}^{-3})$ is

• A. $9.0\times 10^{-23}c{m}^3$
• B. $6.023\times 10^{-23}c{m}^3$
• C. $3.0\times 10^{-23}c{m}^3$
• D. $5.5\times 10^{-23}c{m}^3$

Answer 1

Answer: (C)

(c) $1mole=6.023\times 10^{23}molecule$
$18g=6.02\times 10^{23}molecule$
18 g = mass of $6.02\times 10^{23}$ water molecules
Mass of one water molecule $=\frac{18}{6.023\times 10^{23}}g$
Density $=1gc{m}^{-3}$
$Volume=\frac{Massofonewatermolecule}{Density}$
$=\frac{18}{6.023\times 10^{23}\times 1}=c{m}^3$
$\simeq 3.0x10^{-23}c{m}^3$