Victor Meyer’s method, 0.2 g of an organic substance displaced 56 ml of air at STR The molecular weight of the compound is

Question

Victor Meyer’s method, 0.2 g of an organic substance displaced 56 ml of air at STR The molecular weight of the compound is (A) 56 (B) 112 (C) 80 (D) 28

Tardigrade Admin · Accepted Answer

22400 mol of oxygen contain =1 mol 1 ml of O2 Contains =(1/22400) 56 ml of O2 Contains =(1/22400)× 56 mol Mol=( textwt/ textm .w t. o f organic compound) m . w t. of organic compound =(12× 22400/56 × 10) =80

Q. Victor Meyer’s method, 0.2 g of an organic substance displaced 56 ml of air at STR The molecular weight of the compound is

$56$

$112$

$80$

$28$

$22400 m o l$ of oxygen contain =1 mol
1 ml of $O_{2}$ Contains $= \frac{1}{22400}$
$56 m l$ of $O_{2}$ Contains $= \frac{1}{22400} \times 56 m o l$
$M o l = \frac{wt}{m .w t. o f organic compound}$
m . w t. of organic compound $= \frac{12 \times 22400}{56 \times 10}$
$= 80$