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Q. Victor Meyer’s method, 0.2 g of an organic substance displaced 56 ml of air at STR The molecular weight of the compound is

Organic Chemistry – Some Basic Principles and Techniques

Solution:

$22400\,mol$ of oxygen contain =1 mol
1 ml of $O_{2}$ Contains $=\frac{1}{22400}$
$56\,ml$ of $O_{2}$ Contains $=\frac{1}{22400}\times 56\,mol$
$Mol=\frac{\text{wt}}{\text{m .w t. o f organic compound}}$
m . w t. of organic compound $=\frac{12\times 22400}{56 \times 10}$
$=80$