Thank you for reporting, we will resolve it shortly
Q.
Victor Meyer’s method, 0.2 g of an organic substance displaced 56 ml of air at STR The molecular weight of the compound is
Organic Chemistry – Some Basic Principles and Techniques
Solution:
$22400\,mol$ of oxygen contain =1 mol
1 ml of $O_{2}$ Contains $=\frac{1}{22400}$
$56\,ml$ of $O_{2}$ Contains $=\frac{1}{22400}\times 56\,mol$
$Mol=\frac{\text{wt}}{\text{m .w t. o f organic compound}}$
m . w t. of organic compound $=\frac{12\times 22400}{56 \times 10}$
$=80$