Vertex of the parabola 9 x2-6 x+36 y+9=0, is

Question

Vertex of the parabola 9 x2-6 x+36 y+9=0, is (A) ((1/3),-(2/9)) (B) (-(1/3),-(1/2)) (C) (-(1/3), (1/2)) (D) ((1/3), (1/2))

Tardigrade Admin · Accepted Answer

The given equation 9 x2-6 x+36 y+9=0 can be written as (3 x-1)2=-4(9 y+2). Hence, the vertex is ((1/3),-(2/9)).

Q. Vertex of the parabola $9 x^{2} - 6 x + 36 y + 9 = 0$ , is