Verhulst-PearP is associated with the equation

Question

Verhulst-PearP is associated with the equation (A)  (dN/dt)=rN( (K-N/K) )  (B)  (dN/dt)=tN( (K-N/K) )  (C)  (dN/dt)=rN( (K-N/N) )  (D)  (dN/dt)=tN( (K-N/N) )

Tardigrade Admin · Accepted Answer

Population growth under the Verhulst-Pearl logistic equation is sigmoidal (

S

-shaped), reaching an upper limit termed the carrying capacity,

K

.
Population initiated at densities above

K

decline exponentially untill they reach

K

, which represents the only stable equilibrium.

Q. Verhulst-PearP is associated with the equation

$\frac{d N}{d t} = r N (\frac{K - N}{K})$

$\frac{d N}{d t} = tN (\frac{K - N}{K})$

$\frac{d N}{d t} = r N (\frac{K - N}{N})$

$\frac{d N}{d t} = tN (\frac{K - N}{N})$

Population growth under the Verhulst-Pearl logistic equation is sigmoidal ( $S$ -shaped), reaching an upper limit termed the carrying capacity, $K$ .
Population initiated at densities above $K$ decline exponentially untill they reach $K$ , which represents the only stable equilibrium.

Q. Verhulst-PearP is associated with the equation

dtdN​=rN(KK−N​)

dtdN​=tN(KK−N​)

dtdN​=rN(NK−N​)

dtdN​=tN(NK−N​)

Population growth under the Verhulst-Pearl logistic equation is sigmoidal (S-shaped), reaching an upper limit termed the carrying capacity, K. Population initiated at densities above K decline exponentially untill they reach K, which represents the only stable equilibrium.

$\frac{d N}{d t} = r N (\frac{K - N}{K})$

$\frac{d N}{d t} = tN (\frac{K - N}{K})$

$\frac{d N}{d t} = r N (\frac{K - N}{N})$

$\frac{d N}{d t} = tN (\frac{K - N}{N})$

Population growth under the Verhulst-Pearl logistic equation is sigmoidal ( $S$ -shaped), reaching an upper limit termed the carrying capacity, $K$ .
Population initiated at densities above $K$ decline exponentially untill they reach $K$ , which represents the only stable equilibrium.