Velocity-time (v - t) graph of a particle moving in a straight line is as shown in the figure. The sign of acceleration in regions OP, PQ, QR and RS respectively are

Question

Velocity-time (v - t) graph of a particle moving in a straight line is as shown in the figure. The sign of acceleration in regions OP, PQ, QR and RS respectively are <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/5ee1d25df8da482d01d53d4ddbcbcdf8-.png" /> (A) +, +, -, - (B) -, -, +, + (C) -, +, -, + (D) -, +, +, -

Tardigrade Admin · Accepted Answer

Slope of velocity-time graph is acceleration OP → slope negative PQ → slope positive QR → slope positive RS → slope negative

Q. Velocity-time $(v - t)$ graph of a particle moving in a straight line is as shown in the figure. The sign of acceleration in regions $OP, PQ, QR$ and $RS$ respectively are

$+, +, -, -$

$-, -, +, +$

$-, +, -, +$

$-, +, +, -$

Slope of velocity-time graph is acceleration
$OP \to$ slope negative
$PQ \to$ slope positive
$QR \to$ slope positive
$RS \to$ slope negative

Q. Velocity-time (v−t) graph of a particle moving in a straight line is as shown in the figure. The sign of acceleration in regions OP,PQ,QR and RS respectively are

+,+,−,−

−,−,+,+

−,+,−,+

−,+,+,−