Velocity-time (v-t) graph for a moving object is shown in the figure. Total displacement of the object during the time interval when there is non-zero acceleration and retardation is

Question

Velocity-time (v-t) graph for a moving object is shown in the figure. Total displacement of the object during the time interval when there is non-zero acceleration and retardation is (A)  40m  (B)  (qQ/4π ε 0r)  (C)  (qQ/4π ε 02r2)  (D)  (qQ/4π ε 0r2)

Tardigrade Admin · Accepted Answer

Between time interval 20 s to 40 s, there is non-zero, acceleration and retardation. Hence, distance . travelled during this interval = Area between time interval 20 s to 40 s λ π r3(dB/dt) 1A

Q. Velocity-time (v-t) graph for a moving object is shown in the figure. Total displacement of the object during the time interval when there is non-zero acceleration and retardation is

$40 m$

$\frac{qQ}{4 π ε _{0} r}$

$\frac{qQ}{4 π ε _{0}^{2} r ^{2}}$

$\frac{qQ}{4 π ε _{0} r ^{2}}$

Between time interval 20 s to 40 s, there is non-zero, acceleration and retardation. Hence, distance . travelled during this interval = Area between time interval 20 s to 40 s $λ π r^{3} \frac{d B}{d t}$ $1 A$

Q. Velocity-time (v-t) graph for a moving object is shown in the figure. Total displacement of the object during the time interval when there is non-zero acceleration and retardation is

40m

4πε0​rqQ​

4πε02​r2qQ​

4πε0​r2qQ​

Between time interval 20 s to 40 s, there is non-zero, acceleration and retardation. Hence, distance . travelled during this interval = Area between time interval 20 s to 40 s λπr3dtdB​ 1A

$40 m$

$\frac{qQ}{4 π ε _{0} r}$

$\frac{qQ}{4 π ε _{0}^{2} r ^{2}}$

$\frac{qQ}{4 π ε _{0} r ^{2}}$

Between time interval 20 s to 40 s, there is non-zero, acceleration and retardation. Hence, distance . travelled during this interval = Area between time interval 20 s to 40 s $λ π r^{3} \frac{d B}{d t}$ $1 A$