Velocity of sound waves in air is 330 m/s. For a particular sound in air, a path difference of 40 cm is equivalent to phase difference of 1.6π The frequency of the wave is

Question

Velocity of sound waves in air is 330 m/s. For a particular sound in air, a path difference of 40 cm is equivalent to phase difference of 1.6π The frequency of the wave is (A) 165 Hz (B) 150 Hz (C) 660 Hz (D) 330 Hz

Tardigrade Admin · Accepted Answer

Phase difference =(2 π/λ) × path difference 1.6 π=(2 π/λ) × 40 λ=(2/16) × 40=50 cm =0.5 m v=v λ, v= Velocity of sound v=(u/λ), v= Frequency =(330/0.5)=660 Hz

Q. Velocity of sound waves in air is $330 m / s$ . For a particular sound in air, a path difference of $40 c m$ is equivalent to phase difference of $1.6 π$ The frequency of the wave is

165 Hz

150 Hz

660 Hz

330 Hz

Phase difference $= \frac{2 π}{λ} \times$ path difference
$1.6 π = \frac{2 π}{λ} \times 40$
$λ = \frac{2}{16} \times 40 = 50 c m = 0.5 m$
$v = v λ,$
$v =$ Velocity of sound
$v = \frac{u}{λ},$
$v =$ Frequency
$= \frac{330}{0.5} = 660 Hz$

Q. Velocity of sound waves in air is 330m/s. For a particular sound in air, a path difference of 40cm is equivalent to phase difference of 1.6π The frequency of the wave is