Velocity of a particle changes with position according to following curve. Acceleration of the particle at S = 1 m

Question

Velocity of a particle changes with position according to following curve. Acceleration of the particle at S = 1 m <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/6e443a2604489fab68432f021e9ca042-.png" /> (A) 24 m / s 2 (B) 2 m / s 2 (C) 20 m / s 2 (D) 3 m / s 2

Tardigrade Admin · Accepted Answer

From the graph v=(20/10) s+10 ⇒ v=2 s+10 a=v ⋅ (d v/d s)=2 v=4 s+20 ⇒ a =24 m / s 2

Q. Velocity of a particle changes with position according to following curve. Acceleration of the particle at $S = 1 m$

$24 m / s^{2}$

$2 m / s^{2}$

$20 m / s^{2}$

$3 m / s^{2}$

From the graph
$v = \frac{20}{10} s + 10$
$\Rightarrow v = 2 s + 10$
$a = v \cdot \frac{d v}{d s} = 2 v = 4 s + 20$
$\Rightarrow a = 24 m / s^{2}$

Q. Velocity of a particle changes with position according to following curve. Acceleration of the particle at S=1m

24m/s2

2m/s2

20m/s2

3m/s2