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Physics
Velocity of a particle changes with position according to following curve. Acceleration of the particle at S = 1 m <img class=img-fluid question-image alt=image src=https://cdn.tardigrade.in/img/question/physics/6e443a2604489fab68432f021e9ca042-.png />
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Q. Velocity of a particle changes with position according to following curve. Acceleration of the particle at $S = 1\, m$
Motion in a Plane
A
$24\, m / s ^{2}$
0%
B
$2\, m / s ^{2}$
33%
C
$20\, m / s ^{2}$
0%
D
$3\, m / s ^{2}$
67%
Solution:
From the graph
$v=\frac{20}{10} s+10$
$\Rightarrow v=2 s+10$
$a=v \cdot \frac{d v}{d s}=2 v=4 s+20$
$\Rightarrow a =24 m / s ^{2}$
